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$2^{\omega(n)} \le \tau(n) \le 2^{\Omega(n)}$

Type of Math Object: 
Theorem
Major Section: 
Reference

Mathematics Subject Classification

11A25 no label found

Comments

Why is this theorem classified as unproven? The proof provided convinces me well enough, I don't know about the rest of you.

In cases like this one, just fill a meta correction requesting that it be marked as proven.

The reason is that the "contains own proof" box was not checked.
This happens all the time, either because someone forgets to
change the box or some glich in the system and is no big deal.

Mravinci,

Sometimes when a theorem gets edited, the "contains own proof" box gets unchecked, a bug that yark has pointed out before. I went back and fixed all of the ones to which the user mps filed a correction.

Wkbj79 writes:

> Sometimes when a theorem gets edited, the
> "contains own proof" box gets unchecked,
> a bug that yark has pointed out before.

I don't think I was the first to point this out. But I did point out that (as far as I can tell) it only happens if you use the preview button.

Oh yeah, that explains it. Sometimes when I use the preview button twice, the TeX images look blown up and pixellated, but it doesn't affect the look of the object after saving. Now I know to watch out for this other bug that does affect the saved object. Thanks you yark. Mrav

The proof starts: "Note that the three functions involved in the inequality are multiplicative." I would suggest replacing "functions" with "expressions" - on first reading, my automatic assumption was that the "functions" were \omega(n), \tau(n) and \Omega(n).

Hugo van der Sanden

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